(t/t+1)^2-(2t/t+1)-8=0

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Solution for (t/t+1)^2-(2t/t+1)-8=0 equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

(t/t+1)^2-((2*t)/t)-8-1 = 0

(t/t+1)^2-8-2-1 = 0

4-8-2-1 = 0

4-8-2-1 = 0

-4-2-1 = 0

-6-1 = 0

-7 = 0

-7 = 0

t belongs to the empty set

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